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dusya [7]
3 years ago
13

Rocco runs diagonally across a square field.

Mathematics
1 answer:
valkas [14]3 years ago
7 0
Rocco would have to run diagonally 27 times
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Which statement is true about the equation? 3y-6x=-3
Mekhanik [1.2K]
<span>B.When x=-4, y=-9 and when x=2, y=3.

</span><span>3y-6x=-3
3(-9) - 6(-4)= -3
-27 +24 =-3
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<span>3y-6x=-3
3(3) -6 (2) = -3
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8 0
3 years ago
An icecream shop charges $3.39 for a dish of ice cream. A costomer can also order toppings for $0.59 each. If x represents the n
Leya [2.2K]

Answer:

3.39 + 0.59x

Step-by-step explanation:

Cost of a dish of ice cream = $3.39

Cost of toppings = $0.59 each

x = number of toppings

which expression can be used to determine the total charge in dollars, for a dish of ice cream with x toppings

Total charge for a dish of ice cream with x toppings = 3.39 + 0.59x

The expression is 3.39 + 0.59x

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3 years ago
What type of triangle if any has the Lengths of 11,15,and 25
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Scalene trian<span>gle

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5 0
3 years ago
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what is the product of 4x/x-1 and x^2-1/3x+3 expressed in simplest form? A. 4x/3, B.4x^2/3, C. 4x^2/3x(x+1), D. 4(x+1)/3​
zvonat [6]

Answer:

Step-by-step explanation:

7 0
3 years ago
Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
3 years ago
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