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bixtya [17]
3 years ago
11

Two monomials are shown below.

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
450x^2 y^5 3000x^4 y^3
look at what's common on each exponent first.
for x it would be x^2 and y would be y^1
then divide the x by 150 which is common for both.
150x^2
then for the y you can't do anything else
so your answer is 150x^2 y^1
*NOTE: anything to the first power isn't visible so your answer is 150x^2 y
Read this slow and go step by step. Hope you understand and hope this help answer your question. :)
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Which table represents exponential growth?
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B

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The exponential function y=a^x shows the exponential growth if a>1.

Consider choice B.

If x=1, then y=2=2^1;

if x=2, then y=4=2^2;

if x=3, then y=8=2^3;

if x=4, then y=16=2^4.

This means that the function y=2^x represents the table B.

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A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a
Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.5

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

P(X \leq 4)  + P(X > 4) = 1

We want to find P(X > 4). So

P(X > 4) = 1 - P(X \leq 4)

In which

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061

P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854

P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056

P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222

P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611

So

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898

Finally

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102

91.02% probability of selling more than 4 properties in one week.

8 0
3 years ago
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