Step-by-step explanation:
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Answer:
x = 0
y = -2
Step-by-step explanation:
The given system of equation are:
5x + y = -2
2x - 2y = 4
The problem here is to find x and y from the expression
5x + y = -2 ----- i
2x - 2y = 4 ---- ii
So;
i x 2 : 10x + 2y = -4 ---- iii
ii x 5 : 10x - 10y = 20 ----- iv
iii - iv; 12y = -24
y = -2
Now find x;
5x + y = -2
5x - 2 = -2
x = 0
Step-by-step explanation:
![\text{Let}\ A(x_1,\ y_1)\ \text{and}\ B(x_2,\ y_2).\ \text{Then the distance between}\ A\ \text{and}\ B\ \text{is:}\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y1)^2}\\\\Example:\\\\A(2,\ 5),\ B(-1,\ 1)\\\\|AB|=\sqrt{(-1-2)^2+(1-5)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5](https://tex.z-dn.net/?f=%5Ctext%7BLet%7D%5C%20A%28x_1%2C%5C%20y_1%29%5C%20%5Ctext%7Band%7D%5C%20B%28x_2%2C%5C%20y_2%29.%5C%20%5Ctext%7BThen%20the%20distance%20between%7D%5C%20A%5C%20%5Ctext%7Band%7D%5C%20B%5C%20%5Ctext%7Bis%3A%7D%5C%5C%5C%5C%7CAB%7C%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y1%29%5E2%7D%5C%5C%5C%5CExample%3A%5C%5C%5C%5CA%282%2C%5C%205%29%2C%5C%20B%28-1%2C%5C%201%29%5C%5C%5C%5C%7CAB%7C%3D%5Csqrt%7B%28-1-2%29%5E2%2B%281-5%29%5E2%7D%3D%5Csqrt%7B%28-3%29%5E2%2B%28-4%29%5E2%7D%3D%5Csqrt%7B9%2B16%7D%3D%5Csqrt%7B25%7D%3D5)
Answer:
4 by 2
Step-by-step explanation:
you can basically guess and check with this question but I knew if it was a rectangle then 2 sides would be larger than the other. So I started off figuring out what times what equals 8 and I got 2 and 4. So I put those in for the side lengths and I got 12.