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umka2103 [35]
3 years ago
9

Pls help asap

Mathematics
2 answers:
fomenos3 years ago
6 0
Complementary means the two angles added together would equal 90. So in this case to fine B I have to subtract angle 36 from 90.
KatRina [158]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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A club is selling hats and jackets as a fundraiser. They have to stay within a budget of $900. They can order up to 200 items. E
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8 0
4 years ago
What is the value of [-(-8)]
GuDViN [60]

Answer:

+8

Step-by-step explanation:

this is because when a negative multiplies with another negative it becomes positive

4 0
3 years ago
Use the distributive property to simplify the following expression -2(x+3)
lukranit [14]

Answer:

-2x - 6

Step-by-step explanation:

-2(x + 3)

-2 · x = -2x

-2 · 3 = -6

-2x - 6

5 0
3 years ago
Write a story that could represent this math problem. A rectangle partitioned into thirds five times. The first part, the second
SSSSS [86.1K]

Answer:

The problem is 5 × 2/3 so

Billy paycheck every week was 2/3 a dollar which is approximately 66 cents but one day he did fantastic and got a raise and the raise was 5 times his last paycheck how much money is Billy new paycheck? So we do 5 × 2/3 and that equals 10/3, or 3 1/3, or 3 dollars and 30 cents.

Step-by-step explanation:

just copy and paste it.

7 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
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