well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
Answer:
Step-by-step explanation:
(x – 4)(x – 4) = 0.
So factor are x-4=0
X=4 (D) is the answer
The right answer is "2"
the divisiveness rule says that the number which it's last two digit is divisible to 4 and 2 is divisible to 8 so if you add another digit you have to make it divisible to 4 and 2 which in this case is number "2"
The number in the parentheses is the rate of change. Because this number is less than 1 it is a decrease, so it is a decay.
The percent decrease is 1 - 0.63 = 0.37 = 37% decrease
