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Aleonysh [2.5K]
3 years ago
5

James, a technician, needs to format a new drive on a workstation. He will need to configure read attributes to specific local f

iles and write extended attributes to specific folders. Which of the following file systems will allow him to configure these settings in a Windows environment?A. HFS
B. EXT4
C. FAT32
D. NTFS
Computers and Technology
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

Option D i.e., NTFS.

Explanation:

That technician James may install the latest drive on such a computer. He would also need to customize read attributes from particular local data, and compose expanded characteristics of particular files. NTFS file systems permit you to adjust certain settings in such a Windows environment

So, the following option is correct according to the following scenario.

  • Option(a) is incorrect because It is the file structure that is required to organize information on such a Mac Os hdd.
  • Option (b) is incorrect because using Ext4 to change essential file system DS such as those intended that hold file information.
  • Option(c) is incorrect because It maintains record of most of the documents they have and helps the system find those files on the drive.
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Vladimir [108]

Answer:

import java.util.Scanner;

public class FirstWord {

   public static void main(String[] args) {

       //NOW YOU WANT TO COLLECT INPUTS FROM THE STUDENT OR USER

       //IMPORT THE SCANNER CLASS FIRST  outside your class

       // THEN YOU CREATE AN OBJECT OF THE SCANNER CLASS

       Scanner input = new Scanner(System.in);

       

       //CREATE A VARIABLE TO HOLD THE USER INPUT

       String text = input.nextLine();

       

       //The variable holder will be used to store characters from the for loop

       String holder="";

       

       //Create a for loop that loops through the user's input

       for(int i=0; i<text.length(); i++){

           //As the loop increases, we get the character in the user's input and store them one by one in the variable holder

           holder+=text.charAt(i);

           if(text.charAt(i)==' '){

               //If the loop encounters a space, it means a complete word has been gotten from the user's input

               //Then the break below Breaks the loop, and the loop stops running

               break;

           }

       }

       System.out.println(holder);

}

Explanation:

text.length() returns the length of the sequence of characters present in length

text.charAt(a number) Returns the char value at the specified index. An index ranges from 0 to length() - 1. The first char value of the sequence is at index 0, the next at index 1, and so on, as for array indexing.

Create a for loop

How does a for loop work?

It collects a starting point, an end point and an increment respectively....all these are passed in as arguments into the for loop

For example, the code above starts from 0, calculates the number of characters in the user's input and sets it as the end point, the loop runs from zero to the length of the text of the user...

Note: i++ in the loop is the increment, it means the loop increases by 1

8 0
3 years ago
​What file system below does not support encryption, file based compression, and disk quotas, but does support extremely large v
Elena L [17]

Answer:

D.  ReFS

Explanation:

File system is simply a management system for files that controls how and where data are stored, where they can be located and how data can be accessed. It deals with data storage and retrieval.

Examples of file system are NTFS, FAT(e.g FAT 16 and FAT 32), ReFS.

ReFS, which stands for Resilient File System, is designed primarily to enhance scalability by allowing for the storage of extremely large amounts of data and efficiently manage the availability of the data. It is called "resilient" because it ensures the integrity of data by offering resilience to data corruption. It does not support transaction, encryption, file based compression, page file and disk quotas, to mention a few.

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3 years ago
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nexus9112 [7]

Answer:

int x = 10;

Explanation:

This would work in many languages (C/C++/C#/Java).

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Setler79 [48]

Answer:

void delete_record(student_record *arr, int &size, int age, string name, double gpa) {

int index = -1;

if (arr != NULL && size > 0) {

for (int i = 0; i < size; ++i) {

if (arr[i].age == age && arr[i].name == name && arr[i].gpa == gpa) {

index = i;

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}

}

if (index != -1) {

for (int i = index; i < size - 1; ++i) {

arr[i] = arr[i + 1];

}

size--;

}

}

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