V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)
(dv/dt)*(dt/dh) = dv/dh
dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)
5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)
then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))
The equation of the line in standard form is x + 4y = 8
<h3>How to determine the line equation?</h3>
From the question, the points are given as
(0, 2) and (8, 0)
To start with, we must calculate the slope of the line
This is calculated using
Slope = (y₂ - y₁)/(x₂ - x₁)
Where
(x, y) = (0, 2) and (8, 0)
Substitute the known parameters in Slope = (y₂ - y₁)/(x₂ - x₁)
So, we have
Slope = (0 - 2)/(8 - 0)
Evaluate
Slope = -1/4
The equation of the line can be calculated using as
y - y₁ = m(x + x₁)
Where
(x₁, y₁) = (0, 2)
and
m = slope = -1/4
Substitute the known values in the above equation
So, we have the following equation
y - 2 = -1/4(x - 0)
This gives
y - 2 = -1/4x
Rewrite as
1/4x + y = 2
Multiply by 4
x + 4y = 8
Hence, the line has an equation of x + 4y = 8
Read more about linear equations at
brainly.com/question/4074386
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Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is
Standard deviation of Eskimo dogs is
The range of weights would 99.7% of the dogs have,





Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.
Answer:
$0.90
Step-by-step explanation:
you would divide it by 5
$4.50/5=$0.90
hope this helps
brainliest?
0.5 of a mile - since 5,280ft = 1 mile and half of 5,280 is 2,640