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Dmitry_Shevchenko [17]
1 year ago
5

Solve for y y/8 = 4

Mathematics
1 answer:
Bess [88]1 year ago
4 0

Answer:

32

Step-by-step explanation:

Multiply both sides by 8.

y/8 = 4

y/8 × 8 = 4 × 8

y = 32

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7th grade math help me pleasee :))
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Answer:

step 1 communative property

Step-by-step explanation:

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2 years ago
Given right triangle ABC. To the nearest degree, find the measure of angle B.
DedPeter [7]

Answer:

Step-by-step explanation:

We have the length of AC which is opposite angle B; we also have the length of the hypotenuse.  We will use trig here to solve for angle B.  The sin ratio is the one that fits.

sin(B) = side opposite / hypotenuse:

sin(B)= \frac{ 4.8}{ 5.1} so

sin(B) = .9411764706

Now we will use the 2nd button on our calculators.  This will give us the missing angle value.  Press 2nd then sin and you will see on your screen:

sin^{-1 (

Enter that decimal after the open parenthesis and hit "enter" to get

B = 70.25 or 70°

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3 years ago
7. George has some quarters and some dimes. He has 6 more dimes than quarters and all of
maw [93]

Answer:

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6 0
2 years ago
Read 2 more answers
43. ALGEBRA Assume that your current
RoseWind [281]

Answer:

10582

Step-by-step explanation:

7 0
3 years ago
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The exam scores for 200 students are normally distributed with a mean of 72 and a standard deviation of 10. Which answer choice
Paha777 [63]

Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 72, \sigma = 10

The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.

X = 82:

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 72}{10}

Z = 1

Z = 1 has a p-value of 0.84.

X = 72:

Z = \frac{X - \mu}{\sigma}

Z = \frac{72 - 72}{10}

Z = 0

Z = 0 has a p-value of 0.5.

0.84 - 0.5 = 0.34.

Out of 200 students, the number is given by:

0.34 x 200 = 68 students with scores between 72 and 82.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

6 0
2 years ago
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