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Evgesh-ka [11]
3 years ago
9

Consider the following system of equations: 10 + y = 5x + x2 5x + y = 1 The first equation is an equation of a . The second equa

tion is an equation of a .
Mathematics
2 answers:
hammer [34]3 years ago
8 0

Answer:

parabola

line

Step-by-step explanation:

next couple ones are

0,1,2

then

1, -11 , 56

youre welcome

aleksley [76]3 years ago
5 0

Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.

Explanation:

The first equation is,

10+y=5x+x^2

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.

The second equation is,

5x+y=1

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.

Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.

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3 years ago
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A pencil case with a cylinder shape with diameter= 10 cm
Mila [183]

Answer:

length of the longest pencil that can fit must be less than 13cm

Step-by-step explanation:

To get the longest pencil that fit the case, we will use the pythagoras theorem;

diameter = 10cm

radius = 10/2

radius = 5cm

Height = 12cm

Get the length of the longest side

l² = r²+h²

l² = 5²+12²

l² = 25 + 144

l² = 169

l = √169

l = 13cm

Hence the length of the longest pencil that can fit must be less than 13cm

4 0
3 years ago
Compare and contrast the results of adding or multiplying a value outside the argument of a function to the result of adding or
ki77a [65]

Answer:

Only in special funcitons, specifically linear functions whose graphs pass through the origin, it is the same to put the constant inside the argument or outside

Step-by-step explanation:

If the function has the form f(x) = a*x, where a is a constant, then we have that f(c*x) = a*(c*x) = c*(a*x) = c*f(x). This kind of functions are proportional to the identity function f(x) = x, and they comprehend the linear functions whose graph pass through the origin.

For other linear function this property isnt true. For example if f(x) = x+4, then

f(4) = 4+4 = 8,

f(2*4) = 8+4 = 12

2*f(4) = 2*8 = 16

Thus, 2*f(4) is not f(2*4).

This property also isnt true for quadratic functions for example. If f(x) = x², then f(1) = 1, thus 3*f(1) = 3, however, f(3*1) = 3² = 9.

There might be coincidences for specific values, for example if f(x) = (x-1)*(x-2), then f(2*1)=2*f(1) = 0, however, for any other constant the result is not the same (for example f(0*1) = (-1)*(-2)=2, and 0*f(1) = 0).

If we want a function to satisfy the property f(c*x) = c*f(x) for any c,x, then it should be true that f(c) = f(c*1) = c*f(1). This means that if f(1) = a, then f(c) = c*a, so, in other words, f(x) = a*x = f(1) * x.

5 0
3 years ago
The linear density in a rod 5 m long is 10 x + 4 kg/m, where x is measured in meters from one end of the rod. Find the average d
hichkok12 [17]

The average density of the rod is  0.704 kg/m.

For given question,

We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.

We need to find the

The length of rod is, L = 5 m.

The linear density of rod is, ρ = 10/( x + 4) kg/m

To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,  

The expression for the average density is given as,

⇒ ρ'

=\int\limits^5_0 {\rho} \, dx\\\\=\int\limits^5_0 {\frac{m}{L} } \, dx\\\\=\int\limits^5_0 {\frac{10}{5(x+4)} }\, dx\\\\=\int\limits^5_0 {\frac{2}{x+4} }\, dx                        ......................(1)

Using u = x + 4  

du = dx

u₁ = x₁ + 4

u₁ = 0 + 4

u₁ = 4

and

u₂ = x₂ + 4

u₂ = 5 + 4

u₂ = 9

By entering the values above into (1), we have:

⇒ ρ'

=2\int\limits^9_4 {\frac{1}{u} } \, du\\\\ = 2[(log~u)]_4^{9}\\\\=2[(log~9-log~4)]\\\\=2\times[0.352]

= 0.704

Thus, we can conclude that the average density of the rod is  0.704 kg/m.

Learn more about the average density here:

brainly.com/question/15118421

#SPJ4

3 0
2 years ago
IS (3,4) a solution to y<4x-2
Ksivusya [100]

Answer:

lolololololololololololol

Step-by-step explanation:

lololololololololololol

4 0
3 years ago
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