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prisoha [69]
3 years ago
15

The vertices of triangle FGH are F(4, 1), G(0, 3), and H(2, -1). After a translation of 6 units left and 2 units down, triangle

FGH becomes triangle F'G'H'. After a translation of 1 unit right and 5 units up, triangle F'G'H' becomes triangle F"G"H". What translation would move triangle FGH to triangle F"G"H" directly? a. 6 units left and 2 units down c. 5 units left and 3 units up b. 1 unit left and 5 units up d. 2 units right and 6 units down Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

c. 5 units left and 3 units up

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation is translation, rotation, reflection and rotation.

If a point A(x, y) is translated a units right and b units up, the new location is at A'(x+a, y+b), while if a point A(x, y) is translated a units left and b units down, the new location is at A'(x-a, y-b)

The vertices of triangle FGH are F(4, 1), G(0, 3), and H(2, -1). A translation of 6 units left and 2 units down, triangle FGH becomes triangle F'(-2, -1) G'(-6, 1) H'(-4, -3). A translation of 1 unit right and 5 units up, triangle F'G'H' becomes triangle F"(-1, 4) G"(-5, 6) H"(-3, 2)

The translation of FGH to F"G"H" is a translation of (x -5, y + 3), that is 5 units left and 3 units up

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3(a+1.5)= -1.5 what does a equal
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Answer:

-2

Step-by-step explanation:

3(a+1.5)=-1.5

a+1.5 = - 1.5/3 = - 0.5

a = - 0.5 - 1.5 = - 2

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Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

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Answer:

Select the plain line in the Insert Shapes group. Place your cursor where you want a tick mark on your line, hold the "Shift" key, and drag to create a vertical mark. Holding the Shift key ensures a straight line.

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Which value of m will create a system of parallel lines with no solution? y=mx-6 8x-4y=12 A coordinate grid with one line labele
nydimaria [60]

Answer:

A system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2

Step-by-step explanation:

The equation of the given line is 8·x - 4·y = 12

Which gives;

8·x- 12= 4·y

y = 2·x - 3

Given that the line passes through the points (0, -3) and (1, -1), we have;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

When (x₁, y₁) = (0. -3) and (x₂, y₂) = (1, -1), we have;

Slope, \, m =\dfrac{(-1)-(-3)}{1-(0)} = 2

y - (-3) = 2×(x - 0)

y = 2·x - 3 which is the equation of the given line

For the lines 8·x - 4·y = 12, which is the sane as y = 2·x - 3 and the line y = m·x  - 6 to have no solution, the slope of the two lines should be equal that is m = 2

Given that the line passes through the point (1.5, 0), we have;

y - 0 = 2×(x - 1.5)  

y = 2·x - 3...................(1)

For the equation, y = m·x  - 6, when m = 2, we have;

y = 2·x  - 6..................(2)

Solving equations (1) and (2) gives;

2·x - 3 = 2·x  - 6, which gives;

2·x - 2·x=  - 3 - 6

0 = 9

Therefore, a system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2.

4 0
3 years ago
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