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faust18 [17]
3 years ago
14

A box of cereal states that there are 75 calories in a three fourths 3/4​-cup serving. What is the unit rate for calories per​ c

up? How many calories are there in 2 cups of the​ cereal?
Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

a) The unit rate for calories per​ cup is 100 calories per cup

b) 200 calories in 2 cups of cereal.

Step-by-step explanation:

A box of cereal states that there are 75 calories in a three fourths 3/4​-cup serving.

a) What is the unit rate for calories per​ cup?

This is calculated as:

3/4 cup = 75 calories

1 cup = x

Cross Multiply

3/4x = 75 calories × 1

x = 75 calories /3/4 cup

x = 75 ÷ 3/4

x = 75 × 4/3

x = 100 calories per cup

The unit rate for calories per​ cup is 100 calories per cup

b) How many calories are there in 2 cups of the​ cereal?

From the above question

3/4 cup = 75 calories

2 cups = x

Cross Multiply

3/4x = 75× 2

x = 150 ÷ 3/4

x = 150 × 4/3

x = 200 calories

There are 200 calories in 2 cups of cereal.

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Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
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BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

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