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Mashcka [7]
3 years ago
12

Can't figure this out I've been stuck on it for an hour now. help please

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0
\sqrt{4a^6b^4} =   \sqrt{2^2*(a^3)^2*(b^2)^2} =  2a^3b^2
You might be interested in
What is the area of the figure in the square units?<br> 40<br> 56<br> 64<br> 49
IRISSAK [1]

Answer:

I'm going with 64

Step-by-step explanation:

Add all the numbers and sides

4 0
3 years ago
Choose the equation that is the standard form of
Ronch [10]
For this case we have the following equations:
 5y = 3-2x
 5y-3 = -2x
 2x + 5y = 3
 2x + 5y-3 = 0
 The standard form of the equations is given by:
 Ax + By = C
 Therefore, the equation written in its standard form is:
 2x + 5y = 3
 Where,
 A = 2
 B = 5
 C = 3
 Answer:
 
The equation that is the standard form is:
 
2x + 5y = 3
7 0
3 years ago
-3x-y=-17 4x + 2 y equals 20
ExtremeBDS [4]
-3x - y = -17
4x + 2y = 20

multiply one part of the equation so that we can be able to use the process of elimination.

(-3x - y = -17)2
4x + 2y = 20

Now we have:

-6x -2y = - 34
4x+2y= 20
------------------------
-2x = -14

Divide -2 on both sides.

-2x = -14
/-2       /-2

x = -7.


=============================================

To solve for y, we just have to substitute the value of x to any of the equation given above, that we feel comfortable with. And I'm going to choose this equation: 4x + 2y = 20


4x + 2y = 20

4(-7) + 2y = 20

-28 + 2y = 20

Add 28 on both sides

-28 + 2y = 20
+28          +28
---------------------
2y = 48
/2      /2

y = 24.


The last thing you would do is to check if the answers is correct.
All you have to do is plug in the values of x and y into both equations and see if they equal to one another.

You may have to do this by yourself :P

Anyways, if you have any questions about this topic, feel free to PM me or any other users interested. Thank you for being part of Brainly! Have a nice day!










4 0
3 years ago
Help! Algebra!!!
balandron [24]
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form. 

p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial 

This polynomial has a degree of at least 4. It therefore cannot be cubic. 

Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do. 

(x - 1)(x - 2)(x - 3) 

This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct. 

Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve. I hope this helps</span><span>
</span>
4 0
3 years ago
PLEASE HELP NEED DONE ASAP !! I WILL REWARD BRAINLIEST
strojnjashka [21]
39,916,800 is the answer
4 0
3 years ago
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