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Gekata [30.6K]
2 years ago
13

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

Mathematics
2 answers:
GrogVix [38]2 years ago
7 0

The answer is B. No, the rectangle cannot have x=20 and y=11 because x + y does not equal 32.

The reasoning is, 20 + 11 = 31. In order to find the perimeter around the whole object, you will need to multiply 31 by 2 and get 62.

But, x is ONLY 20 and y is ONLY 11. It is not saying x(2) and y(2), so your answer has to be B.

vekshin12 years ago
5 0
B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

Perimeter = 2(l + w)
Perimeter = 64

Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.


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<h3>How to determine the angles of a triangle inscribed in a circle</h3>

According to the figure, the triangle BTC is inscribed in the circle by two points (B, C). In this question we must make use of concepts of diameter and triangles to determine all missing angles.

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By geometric and algebraic properties the angles BTC, TBC and TBC from the triangle BTC are 128°, 26° and 26°, respectively.

To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/2773823

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