The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?
2 answers:
The answer is B. No, the rectangle cannot have x=20 and y=11 because x + y does not equal 32.
The reasoning is, 20 + 11 = 31. In order to find the perimeter around the whole object, you will need to multiply 31 by 2 and get 62.
But, x is ONLY 20 and y is ONLY 11. It is not saying x(2) and y(2), so your answer has to be B.
B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
Perimeter = 2(l + w)
Perimeter = 64
Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.
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