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lyudmila [28]
2 years ago
9

WSP CAN SOMEONE ACTUALLY HELP N EXPLAIN IM LOST

Mathematics
2 answers:
Alex787 [66]2 years ago
5 0

Answer:

Option A

Step-by-step explanation:

Given expression:

  • 3x² - 10x - 8

<u>Option A</u>

⇒ (x - 4)(3x + 2)

⇒ (x × 3x) + (2 × x) + (-4 × 3x) + (-4 × 2)

⇒ (3x²) + (2x) + (-12x) + (-8)

⇒ 3x² + 2x - 12x - 8

⇒ 3x² - 10x - 8

3x² - 10x - 8 = 3x² - 10x - 8 (Yes!)

<u>Option B</u>

⇒ (3x - 4)(x - 2)

⇒ (3x × x) + (3x × -2) + (-4 × x) + (-4 × -2)

⇒ (3x²) + (-6x) + (-4x) + (8)

⇒ 3x² - 6x - 4x + (8)

⇒ 3x² - 10x + 8

3x² - 10x - 8 = 3x² - 10x + 8 (No!)

<u>Option C</u>

⇒ (3x - 4)(x + 2)

⇒ (3x × x) + (3x × 2) + (-4 × x) + (-4 × 2)

⇒ (3x²) + (6x) + (-4x) + (-8)

⇒ 3x² + 6x - 4x - 8

⇒ 3x² + 2x - 8

3x² - 10x - 8 = 3x² + 2x - 8 (No!)

<u>Option D</u>

⇒ (3x - 2)(x - 4)

⇒ (3x × x) + (3x × -4) + (-2 × x) + (-2 × -4)

⇒ (3x²) + (-12x) + (-2x) + (8)

⇒ 3x² - 12x - 2x + 8

⇒ 3x² - 14x + 8

3x² - 10x - 8 = 3x² - 14x + 8 (No!)

Since the expression of option A has the same value as the given expression, option A is correct.

Licemer1 [7]2 years ago
4 0

Answer:

Hi! Let's find which expression is equivalent to 3x^{2} - 10x - 8. First, remember that expressions are equivalent when they have identical solutions or roots. That means we have to do three things:

- solve 3x^{2} - 10x - 8

- review the listed expressions

- determine which solution is equivalent to the solution of 3x^{2} - 10x - 8

First, let's solve 3x^{2} - 10x - 8.

Use the sum-product pattern -

3x^2 - 10x - 8

3x^2 + 2x - 12x - 8

Common factor from the two pairs -

3x^2 + 2x - 12x - 8

x(3x + 2) - 4(3x + 2)

Rewrite in factored form -

x(3x + 2) - 4(3x + 2)

(x - 4)(3x + 2)

Now, let's review the listed expressions. We have:

A. (x - 4)(3x + 2)

B. (3x - 4)(x - 2)

C. (3x - 4)(x + 2)

D. (3x - 2)(x + 4)

We're looking for one of these expressions to be equivalent to the solution of 3x^{2} - 10x - 8, which we know is (x - 4)(3x + 2). The first choice, A. (x - 4)(3x + 2), would be our answer!

I hope this helps you. Have a wonderful day and let me know if I can help you with anything else! =)

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