Question

Please help me with the math question

Answer 1

Answer:

• neither even nor odd
• degree 5
• LC negative
• roots {-6, -4, 0, 2, 3}

Step-by-step explanation:

The function's graph is not symmetrical about the origin, so it is not an odd function. It is not symmetrical about the y-axis, so is not an even function.

The function is neither even nor odd.

There are 5 zero-crossings and no places where y=0 and the graph does not cross. This means the function is of degree 5, at least.

The general shape of the function is down and to the right, so the sign of the function for large values of x is opposite the sign of x. The leading coefficient must be negative.

As we noted, there are 5 zero-crossings. These are the real roots. They are found at x-values in the set {-6, -4, 0, 2, 3}.