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Colt1911 [192]
4 years ago
15

Please help me with the math question

Mathematics
1 answer:
IgorC [24]4 years ago
8 0

Answer:

  • neither even nor odd
  • degree 5
  • LC negative
  • roots {-6, -4, 0, 2, 3}

Step-by-step explanation:

The function's graph is not symmetrical about the origin, so it is not an odd function. It is not symmetrical about the y-axis, so is not an even function.

The function is neither even nor odd.

There are 5 zero-crossings and no places where y=0 and the graph does not cross. This means the function is of degree 5, at least.

The general shape of the function is down and to the right, so the sign of the function for large values of x is opposite the sign of x. The leading coefficient must be negative.

As we noted, there are 5 zero-crossings. These are the real roots. They are found at x-values in the set {-6, -4, 0, 2, 3}.

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Use your calculator to select the best answer below:
bixtya [17]

Answer:

-2\sqrt{a}

Step-by-step explanation:

\lim_{x \to a} \frac{a-x}{\sqrt{x} -\sqrt{a} } \\ =-\lim_{x \to a} \frac{x-a}{\sqrt{x} -\sqrt{a} }  \\=-\lim_{x \to a} \frac{(\sqrt{x} -\sqrt{a})(\sqrt{x} +\sqrt{a})}{\sqrt{x} -\sqrt{a} }  \\=- \lim_{x \to a} \sqrt{x} +\sqrt{a}\\=-2\sqrt{a}

6 0
3 years ago
Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?
Veronika [31]

Answer:

A) 2k+4

Step-by-step explanation:

To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.

To start, we will cross multiply. If we have a/b=c/d, then ad=bc

We can perform the same calculation here,

6/x=3/(k+2)

6(k+2)=3x

Divide both sides by 3

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7 0
4 years ago
URGENT!!!
ludmilkaskok [199]

Answer:

the combination of numbers must then be:

9.7 + 8.6 which results to 18.3

9.6 + 8.7 yields 18.3 as well.

LMK if I was wrong.

Yours Truly.

6 0
4 years ago
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