Answer:
See below.
Step-by-step explanation:
Just like 18, continue with 19-21. Solve for x by rewriting each equation in log form.
When rewriting the form, the base of the exponent becomes the base of the log.
8/3 cups or 2 2/3
2/3 × 4/1 = 8/3
if u divide 3 into 8 it gives u 2 times with 2 places left
the 2 places equal 2/3
2 whole OR 6/3 + 2/3 = 8/3 OR 2 and 2/3
Answer:
x=-10 is your answer
Step-by-step explanation:
2(-2x+2)+x+3=37
-4x+4+x+3=37
-4x+4+x=34
-4x+x=30
-3x=30
x=-10
180 - 124 = 56
4x = 180 - (56 + 60)
4x = 180 - 116
4x = 64
x = 16
answer
B. 16
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
