Answer:
3/5
Step-by-step explanation:
I just looked up how to do this since I've never done it before, so if I'm wrong I'm sorry, but from what I found all you have to do is put the opposite(o) over the hypotenuse(h) o/h which would be 9/15 and simplified it would be 3/5, and again if I'm wrong I'm sorry.
I hope this helps, and have a great day!
You need the first term and the common ratio.
A quarter of an hour is 15 minutes, so a quarter past 7 is 7+15 mins. This gives you:
7:15
Hope this helps and good luck!
Answer: No solution
Step-by-step explanation:
Since putting it in by y=mx+b and there is no solution
Given:
Number of students who has a cat and a dog = 5
Number of students who has a cat but do not have a dog = 11
Number of students who has a dog but do not have a cat = 3
Number of students who neither have a cat nor a dog = 2
To find:
The probability that a student has a cat given that they do not have a dog.
Solution:
Let the following events:
A = Student has a cat
B = Do not have a dog
Total number of outcomes is:

The probability that a student has a cat but do not have a dog is:

The probability that a student do not have a dog is:


The conditional probability is:



Therefore, the probability that a student has a cat given that they do not have a dog is
.