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3 years ago

Solve the following equations for x (5 points each). (a)-3x+10=34

Mathematics

1 answer:

yan [13]3 years ago

6 0

Answer:

x = -8

Step-by-step explanation:

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When a problem asks for f(5), what is it asking for?

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A. the value of f(x) when x = 5

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Please help me prove that ED is congruent to BA! I thought I had it right by proving right and vertical angles, but I’m missing

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Step-by-step explanation:

$\overline{DA} \text{ bisects } \overline{EB}$ is given

$\overline{BC} \cong \overline{EC}$ definition of <u>bisect</u>

<u /> $\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}$ are both given

<u /> $\angle B, \, \angle E \text{ are right angles}$ definition of perpendicular

$\angle B \cong \angle E$ because all right angles are congruent

$\angle{ACB} \cong \angle{DCE}$ vertical angles are congruent

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3 years ago

Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter

Lerok [7]

Answer:

There are no possible solutions

Step-by-step explanation:

Given:

Minimum number of coins Alexa has =28 coins

Number of quarters Alexa has = 17 quarters

Total amount in coins = $5.05 = 505 cents

Let number of dimes be = $x$ coins

So we can have two inequalities.

1) Total number of coins

$x+17\geq28\\$ [Since minimum number of coins=28]

2) Total value of coins

$10x+(25)(17)\leq505$ [As 1 dime=10 cents and 1 quarter=25 cents]

$10x+425\leq505$

Solving inequality (1)

Subtracting both sides by 17.

$x+17-17\geq28-17$

∴ $x\geq 11$

Solving inequality (2)

Subtracting both sides by 425.

$10x+425-425\leq505-425$

$10x\leq 80$

Dividing both sides by 10.

$\frac{10x}{10}\leq \frac{80}{10}$

∴ $x\leq 8$

On combining both solutions

$x\geq 11$ and $x\leq 8$ ,

we see that there are no possible solutions as number of dimes cannot be ≥11 and ≤8 at the same time.

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3 years ago

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Answer:

$28,000

Step-by-step explanation:

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