I think it would be “no fine is paid is returned by due date”
Hope this helps!
Answer:
The probability that exactly three of them are comfortable with delivery by drones is 0.2583.
Step-by-step explanation:
Let <em>X</em> = number of consumers comfortable having drones deliver their purchases.
The probability of the random variable <em>X</em> is, P (X) = <em>p</em> = 0.43.
Then <em>q</em> is, <em>q</em> = 1 - p
A sample of <em>n</em> = 5 consumers are selected.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The pmf of <em>X</em> is:

Compute the value of P (X = 3) as follows:

Thus, the probability that exactly three of them are comfortable with delivery by drones is 0.2583.
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.