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ahrayia [7]
3 years ago
8

(1 MATH QUESTION MULTIPLE CHOICE) NEED CORRECT ANSWER

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

Answer: C

They are a reflection and congruent by side, side, side. Correspond is the part which corresponds and is also equal.

Here Angle S corresponds and is congruent to Angle R in these congruent triangles.

Angle P is congruent and corresponds to Angle T for these congruent triangles

Angle Q is equal to Angle Q as they are vertical angles across a vertex.

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Use Lagrange multipliers to find the maximum and minimum values of f(x, y, z) = x − 2y + 5z on the sphere x 2 + y 2 + z 2 = 30.
Gekata [30.6K]

Answer:

Maximum: ((1,-2,5) ; 30)

Minimum: ((-1,2,-5) ; -30)

Step-by-step explanation:

We have the function f(x,y,z) = x - 2y + 5z, with the constraint g(x,y,z) = 30, with g(x,y,z) = x²+y²+z². The Lagrange multipliers Theorem states that, the points (xo,yo,zo) of the sphere where the function takes its extreme values  should satisfy this equation:

grad(f) (xo,yo,zo) = λ * grad(g) (xo,yo,zo)

for a certain real number λ. The gradient of f evaluated on a point (x,y,z) has in its coordinates the values of the partial derivates of f evaluated on (x,y,z). The partial derivates can be calculated by taking the derivate of the function by the respective variable, treating the other variables as if they were constants.

Thus, for example, fx (x,y,z) = d/dx x-2y+5z = 1, because we treat -2y and 5z as constant expressions, and the partial derivate on those terms is therefore 0. We calculate the partial derivates of both f and g

  • fx(x,y,z) = 1
  • fy(x,y,z) = -2
  • fz(x,y,z) = 5
  • gx(x,y,z) = 2x (remember that y² and z² are treated as constants)
  • gy(x,y,z) = 2y
  • gz(x,y,z) = 2z

Thus, for a critical point (x,y,z) we have this restrictions:

  • 1 = λ 2x
  • -2 = λ 2y
  • 5 = λ 2z
  • x²+y²+z² = 30

The last equation is just the constraint given by g, that (x,y,z) should verify.

We can put every variable in function of λ, and we obtain the following equations.

  • x = 1/2λ
  • y = -2/2λ = -1/λ
  • z = 5/2λ

Now, we replace those values with the constraint, obtaining

(1/2λ)² + (-1/λ)²+(5/2λ)² = 30

Developing the squares and taking 1/λ² as common factor, we obtain

(1/λ²) * (1/4 + 1 + 25/4) = (1/λ²) * 30/4 = 30

Hence, λ² = 1/4, or, equivalently,\lambda =^+_- \frac{1}{2} .

If \lambda = \frac{1}{2} , then 1/λ is 2, and therefore

  • x = 1
  • y = -2
  • z = 5

and f(x,y,z) = f(1,-2,5) = 1 -2 * (-2) + 5*5 = 30

If \lambda = - \frac{1}{2} , then 1/λ is -2, and we have

  • x = -1
  • y = 2
  • z = -5

and f(x,y,z) = f(-1,2,-5) = -1 -2*2 + 5*(-5) = -30.

Since the extreme values can be reached only within those two points, we conclude that the maximun value of f in the sphere takes place on ((1,-2,5) ; 30), and the minimun value takes place on ((-1,2,-5) ; -30).

5 0
4 years ago
Math question down below
Elza [17]
The answer is 9 3/7 the last one
6 0
4 years ago
Read 2 more answers
3x – 2y = -6<br> y = 1.5x + 3<br> What is the solution to the system
Igoryamba

Answer:

The answer is D infinitely many

Step-by-step explanation:

6 0
3 years ago
Find the measure of angleq, the smallest angle in a triangle whose sides have lengths 4, 5, and 6. round the measure to the near
Pavlova-9 [17]

The measure of the ∠Q = 41°

By law of cosines:

a law in trigonometry: the square of a side of a plane triangle equals the sum of the squares of the remaining sides minus twice the product of those sides and the cosine of the angle between them.

Which can we stated as:

{q}^2 = {p}^2 + {r}^2 - 2prcos(Q)\\{4}^2 = {6}^2 + {5}^2 - 2*6*5*cos(Q)\\\\

solving equation using normal algebra:

60cos(Q) = 36 + 25 - 16

60 cos(Q) = 45

cos(Q) = 45/60

cos(Q) = 3/4

Q = {cos}^{-1} (\frac{3}{4})\\

Thus, Q = 41°

Hence, the measure of the smallest angle in a triangle whose sides have lengths 4, 5, and 6. ∠Q is 41°.

To learn more about Finding angles visit:

brainly.com/question/3067469

#SPJ4

5 0
2 years ago
Determine if (3, 7) is a Solution or not Solution to the linear system.
spayn [35]

Answer:

y = 2x + 1 --> linear

y = -4x + 7 --> non-linear

Not a solution for linear system.

Step-by-step explanation:

for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:

7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.

for (b), we have to substitute our values again. You get:

7 = -4x3 + 7, which is

7 = -12+7, which is not true. So, (b) is not linear.

This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.

7 0
3 years ago
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