Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
In cylindrical coordinates, we have 
, so that
correspond to the upper and lower halves of a sphere with radius 
. In spherical coordinates, this sphere is 
.
means our region is between two cylinders with radius 1 and . In spherical coordinates, the inner cylinder has equation
This cylinder meets the sphere when
which occurs at
where 
. Then 
.
The volume element transforms to
Putting everything together, we have
Carbon Dioxide: o2c
Water: h2o
Oxygen: o2
Water is h2o because there are 2 hydrogen molecules and 1 oxygen molecule.
h2 = 2 hydrogen molecules
o = 1 oxygen molecule
Answer:
C
Step-by-step explanation:
so the first one ends at 4.7107
the second- 3.3568
the third- 5.1401
and multiplying the first by 5000 we get- 23,553.5
for the second we get -6,713.6
for the third we get 41,120
adding them all together we get 71,387.1
and so C is the closest
