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vladimir2022 [97]
3 years ago
14

Help how do i solve this for the inverse

id="TexFormula1" title="f(x) = \frac{x - 2}{3} " alt="f(x) = \frac{x - 2}{3} " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Vanyuwa [196]3 years ago
7 0

Answer:

\boxed{f^{-1}(x)=3x+2}

Step-by-step explanation:

f(x)=\dfrac{x-2}{3}\to y=\dfrac{x-2}{3}\\\\\text{exchange x and y}\\\\x=\dfrac{y-2}{3}\\\\\text{solve for y}\\\\\dfrac{y-2}{3}=x\qquad\text{multiply both sides by 3}\\\\y-2=3x\qquad\text{add 2 to both sides}\\\\y=3x+2

Karolina [17]3 years ago
3 0

Answer:

The inverse function is 3x+2

Step-by-step explanation:

To get the inverse function exchange x and y  and then solve for y

y = (x-2)/3

Exchange x and y

x = (y-2)/3

Solve for y

Multiply by 3

3x = 3/3 *(y-2)

3x = y-2

Add 2 to each side

3x+2 = y-2+2

3x+2 =y

The inverse function is 3x+2

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Rectangles J and K are similar. If the area of rectangle J is 440, what is the area of rectangle K? I need this today
Hunter-Best [27]

Answer:

Area = 27.5

Step-by-step explanation:

Given

J_{Area} = 440

J_{Width} = 22

K_{Width} = 5.5

<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle  J

J_{Length} * J_{Width} = J_{Area}

This gives:

J_{Length} * 22 = 440

Divide both sides by 22

\frac{J_{Length} * 22}{22} = \frac{440}{22}

J_{Length} = 20

So, the length of the rectangle J is 20.

Since both shapes are similar, then:

J_{Length} : J_{Width} = K_{Length} : `K_{Width}

Substitute the known values:

20 : 22 = K_{Length} : `5.5

Express as fraction:

\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}

Make Length, the subject of formula

K_{Length} = \frac{5.5 * 20}{22}

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K_{Length} = 5

The area of K is:

Area = K_{Length} * K_{Width

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Dima020 [189]

Answer:

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Please choose an answer and tell me why you chose that
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Answer:

A

Step-by-step explanation:

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