Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
The volume of a cube is V=x³ where x is the side length. The volume of a cube can also be written as V=lwh, where l is length, w is width and h is height. since the given side length to us is 9.2, we can put that into the formula.
V=9.2³, or V=9.2*9.2*9.2
V=778.688in³
Ok so for number one is 6in the radius? And for number two your answer is C. 250 in. Squared.
Answer:
x + 3 greater than or equal to 8 would be the solution