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RideAnS [48]
3 years ago
11

What is LCM of two numbers if one number is a multiple of the other? give an example

Mathematics
1 answer:
GuDViN [60]3 years ago
8 0
If one is a multiple of the other, then the larger one is the LCM of the pair.

The LCM of  2  and  6  is  6 .

The LCM of  5  and  15  is  15 . 

The LCM of  7  and  14  is  14 .
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A bag has four green marbles, three red marbles, and three yellow marbles. What is the probability that you pick a red marble, d
Archy [21]
The probability is 1/9
5 0
4 years ago
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What is equivalebt to 6/12
Savatey [412]
3/6
 because 6 divided by 2 = 3 
and
12 divided by 2 = 6
4 0
3 years ago
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Find the parabola through
Anni [7]

Answer:

y = - 3x² - 24x - 60

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 12 ), thus

y = a(x + 4)² - 12

To calculate a substitute (- 7, - 39) into the equation

- 39 = a(- 7 + 4)² - 12 ( add 12 to both sides )

- 27 = 9a ( divide both sides by 9 )

- 3 = a

y = - 3(x + 4)² - 12 ← in vertex form

Expand (x + 4)²

y = - 3(x² + 8x + 16) - 12

   = - 3x² - 24x - 48 - 12

y = - 3x² - 24x - 60 ← in standard form

   = - 3(x²

3 0
3 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)
dybincka [34]

Answer:

amplitude; \frac{2}{3}

Phase shift; \pi units right

Period;\frac{2\pi}{3}

Step-by-step explanation:

The given function is

y=-\frac{2}{3}\cos(3t-3\pi)

This function is of the form;

y=A\sin (Bt+C)

The period is given by:

|A|=|-\frac{2}{3}|= \frac{2}{3}

The period is given by:

T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}

The phase shift is given by;

\frac{C}{B}=\frac{-\3pi}{3}=- \pi or \pi units right.

4 0
3 years ago
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