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Vaselesa [24]
3 years ago
6

Marco's mom has measured his height in centimeters every few months between the ages of 4.5 and 7.5. The recorded values are bes

t estimated by the regression line with the equation y with hat on top equals space 80.46 space plus space 6.25 x. Marco's mom wants to use this equation to predict if Marco will be taller than her when he is 14 years old. Doing this prediction is an example of what
Mathematics
1 answer:
Contact [7]3 years ago
7 0

Answer:

Extrapolation

Step-by-step explanation:

Extrapolation is a type of estimation, beyond the original observation range. In this case, the observation range is from 4.5 to 7.5 years. Marco's mom is extrapolating the regression line to estimate Marco's height at 14 years old. This sort of estimation assumes that Marco's height will continue changing at the same rate until he is 14 years old.

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<u>Parallel lines</u> are lines that run side-by-side without touching or intersecting!

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Sets of parallel lines:

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Sets of perpendicular lines:

  • CD and AB
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2 years ago
What is the greatest common factor of 60,90, and 120
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60/2 = 30
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3 years ago
Which is the next step in the following construction of an equilateral triangle
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Step-by-step explanation:

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2 years ago
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

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3 years ago
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