ANSWER:
- x – 3y = 2 ...(1)
- 2x – 6y = 6 ...(2)
On solving eq(1), we get
Plug the value of x in eq(2)
- 2x – 6(x - 2/3) = 6
- 2x – 2(x – 2) = 6
- 2x – 2x + 4 = 6
- 0 = 6 – 4
- 0 ≠ 2
So, given system of equations is not correct.
<span>The partial derivative of the given function with respect to x is
a - by/cx2 + dy/dx
In this derivative the terms in the with x is only considered other or treated as constant
The partial derivative of the given function with respect to y is
b/cx+ d2y/dx.
In this derivative the terms in the with x is only considered other or treated as constant</span>
Answer:
33%
Step-by-step explanation:
Assuming the weight of the mixture to be 100g**, then the weight of ryegrass in the mixture would be 30g.
Also, assume the weight mixture X used in the mixture is Xg, then the weight of mixture Y used in the mixture would be (100-X)g.
So we can now equate the parts of the ryegrass in the mixture as:
0.4X + 0.25(100-X) = 30
<=> 0.4X + 25 - 0.25X = 30
<=> 0.15X = 5
<=> X = 5/0.15 = 500/15 = 100/3
So the weight of mixture X as a percentage of the weight of the mixture
= (weight of X/weight of mixture) * 100%
= (100/3)/100 * 100%
= 33%
Answer:
The perimeter of the square is 76ft.
