4 years ago

The Nth term of a sequence is 3n^2 /2

Mathematics

1 answer:

Setler [38]4 years ago

7 0

a. Second term= 3(2)^2/2

6^2/2=36/2=18

b. Fifth term=3(5)^2/2

15^2/2=225/2

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Let,
Length = a
Width= b

a-b=4 --eq(1)
since perimeter of parallelogram P=2(a+b)
therefore
2a+2b=72 --eq(2)

eq(1)=>
a=b+4

substitute the value of a in eq 2

Eq(2)=>
2(b+4)+2b=72
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Substitue the value of b in eq(1)

Eq(1)=>
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To solve this problem, we have to use the interior angles theorem which states that the sum of all three interior angles of a triangle must sum 180°.

Having said that, we express the following.

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Now, we solve for <em>x</em>.

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