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Zarrin [17]
3 years ago
5

When finding the median, do we have to put the numbers in order from least to greatest

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0
Yes you do. Place all of the numbers, even repeating ones, in order from slammers to largest and then start crossing out from both sides until you get the middle. For example, in the problem below the median would be 4 bc it’s in the middle

1,2,2,3,4,6,6,7,8
White raven [17]3 years ago
4 0
There are usually multiple ways to solve any math problem.

You don't have to put the numbers in order if there's another way to find a value such that the number of numbers greater than that value is equal to the number of numbers less than that value.*

It is usually easiest to put the numbers in order, but it is not absolutely necessary.

_____
* If the size of the set is odd, then the value found must be in the set. If the size of the set is even, the value found must be the average of the two numbers in the set that are nearest and either side of that value.
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What is the value of f (x) = 1/2 x + 5 when x=4
Anna35 [415]
Replace all values of x as 4

f(4)=1/2(4)+5
f(4)=4/2+5
f(4)=2+5
f(4)=7

Hope I helped :)
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4 years ago
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Why should the number of classes in a frequency distribution be between 5 and​ 20?
Free_Kalibri [48]

Answer:

To allow for easy segregation, analysis, detecting patterns and understanding of the data

Step-by-step explanation:

Classes are, in simple terms, grouping of data based on certain unique characteristics.

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3 0
4 years ago
What is x? <br> 4x+10=-26 <br> A.-4 B-9 C. 9
WITCHER [35]
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6 0
4 years ago
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Figure RHOM is a rhombus. and are the diagonals of the rhombus, as well as angle bisectors of the vertex angles, and they create
Ganezh [65]

Answer:

∠MSR is right angle


Step-by-step explanation:

It is given that RHOM is a Rhombus

Also ΔHOM, ΔMHR, ΔRHO and ΔOMR are isosceles triangles

Let us take ΔMSR and ΔRSH

∠MRS =∠HRS            ( since it is given that the diagonal RO bisects ∠R)

∠RMS =∠RHS     ( since Δ MRH is isosceles triangle )

RS = RS        ( common side )

By AAS congruency rule ΔMSR ≅ ΔHSR

so we have

∠MSR=∠RSH  ( corresponding parts of congruent triangles are congruent)

also we have

∠MSR +∠RSH =180°   ( supplementary angles)

∠MSR +∠MSR=180°          ( since ∠MSR=∠RSH)

2∠MSR= 180°

∠MSR =90°

Hence ∠MSR is right angle


6 0
3 years ago
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