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aleksandr82 [10.1K]
2 years ago
8

an envelope from the post office is 3 inches wide with a total area of 30 square inches what is the height of the envelope

Mathematics
1 answer:
matrenka [14]2 years ago
3 0
Jgthhmgmh,n Kong gmail,k Lukas out ivy. Go ftyfy
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a Textbook weighs 2.5 pounds. how many kilograms does the textbook weigh? round your answer to the nearest tenth of a pound. one
Rzqust [24]
If you round it to the nearest pound it is 1.1 kg
2.5/2.2 = 1.13....
3 0
3 years ago
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Are the triangles congruent if they are which theorem and why?
leonid [27]
Yes the sides are equal to each other
7 0
2 years ago
You have a total of 52 respondents to a survey
Rama09 [41]

Answer:

17% , 15% , 6% , 10% , 40% , 6%

Step-by-step explanation:

You're going to have to divide the number of people who voted for those positions by the total number of people.

Adapting = 9 / 52 = 17%

Other = 8 / 52 = 15%

Yes = 3 / 52 = 6%

No = 5 / 52 = 10%

Absolutely = 21 / 52 = 40%

Maybe = 3 / 52 = 6%

6 0
2 years ago
Two garden plots are to have the same area. One is square and one is rectangular. The rectangular plot is 4 meters wide and 16 m
AlexFokin [52]

side = 8 m

the area of the rectangle = length × width = 16 × 4 = 64 m²

the area of the square = s² ( where s is the length of a side ), hence

s² = 64 ( since areas are equal )

take the square root of both sides

s = √64 = 8 m


7 0
2 years ago
The side of a square is 2.5 cm. Find its perimeter and area.​
Neko [114]

Answer:

Perimeter = 10 cm

Area = 6.25 cm²

Step-by-step explanation:

\bf \: Given :

\sf \: Side  \:  of \:  the \:  square = 2.5 \: cm

\bf \: To \:  find:

\rightarrow \sf \: Perimeter

\sf\rightarrow Area

\bf \: Solution :

\rm \: First \:  w e \:  need \:  to \:  find  \: out  \: the  \: perimeter \:  o f \:  it.

So to find the Perimeter of the square, we'll use this formula :

\boxed{  \sf\longrightarrow \: Perimeter = 4 \times side}

\bf \: Step  \: 1 : \rm \:  Put \:  the  \: value  \: of   \: side \:  of \:  the  \: square :

\sf\longrightarrow \: Perimeter = (4 \times 2.5)cm

\bf \: Step\;2 : \rm Multiply :

\sf\longrightarrow \: Perimeter  = 10 \: cm

Hence, the perimeter would be 10 cm .

\rule{225pt}{2pt}

\sf \: Now,\; let's\; find  \: the  \: Area .

We know that the formula of Area to find the square is,

\boxed{ \sf \longrightarrow \: Area = (side) {}^{2} }

Note : The answer would always be in cm².

\bf Step\;  1  :\rm Put\;  the\; value \; of\;  side \; of \; the\; square :

\sf\longrightarrow{Area} = (2.5) {}^{2}  \: cm {}^{2}

\sf\longrightarrow{Area} = (2.5 × 2.5 ) \: cm {}^{2}

\bf \: Step\;2 : \rm Multiply :

\longrightarrow\sf \: Area = 6.25 \: cm {}^{2}

Hence, the area of the square would be 6.25 cm².

<em>We are done !</em>

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

:D

3 0
2 years ago
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