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zvonat [6]
3 years ago
7

suppose the population of a certain city is 4569 thousand. It is expected to decrease 3690 thousand in 50 years. Find the percen

t decrease.​
Mathematics
1 answer:
stiv31 [10]3 years ago
6 0
Change over Oringinal
879/4569= 19.23%
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Answer:

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

Step-by-step explanation:

A Type I error happens when a true null hypothesis is rejected.

In this case, as the claim that want to be tested is that the average wind speed is significantly higher than 15 mph, the null hypothesis has to state the opposite: the average wind speed is equal or less than 15 mph.

Then, with this null hypothesis, the Type I error implies a rejection of the hypothesis that the average wind speed is equal or less than 15 mph. This is equivalent to say that there is evidence that the average speed is significantly higher than 15 mph.

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

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2 years ago
What does 5-(-3)=? help asap​
Charra [1.4K]

Answer:

The correct answer is 8

Step-by-step explanation:

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6 0
3 years ago
One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second co
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Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container =x \times \frac{30}{100} = 0.3 x

The amount of acid in second container =1.5x \times \frac{50}{100}  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = \frac{1.05x}{2.5x} \times 100% %

                                                                     = 42%

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3 years ago
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Answer:

Step-by-step explanation:

B. Yes, because it passes the vertical line test, is the answer.

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