The length of a rectangular deck is 3 times its width. If the deck’s perimeter is 32 feet, what is the deck’s area?

Convert the given measurements to the new units to be 37cm

brilliants [131]

Answer:

37cm = 370 millimeters

37cm = 0.37 meter

37cm = 0.00037 kilometers

Step-by-step explanation:

$1cm = 10 millimeters \\\\1 cm = \frac{1}{100} meter\\\\1cm = \frac{1}{100000} kilometer\\\\$

37cm = 370 millimeters

37cm = 0.37 meter

37cm = 0.00037 kilometers

6 0

3 years ago

Hola pueden ayudar a=6cm b=8cm c?

Alexxandr [17]

Answer:

c=10cm

Step-by-step explanation:

a²+b²=c²

6²+8²=c²

36+64=c²

100=c²

10=c

6 0

2 years ago

The image of a parabolic lens is projected onto a graph. The image crosses the x-axis at –2 and 3. The point (–1, 2) is also on

Ierofanga [76]

Answer:

$y =-\frac{1}{2}(x +2)(x - 3)$

Step-by-step explanation:

Given

$x_1 = -2$

$x_2 = 3$

$(x,y) = (-1,2)$ --- a point on the parabola

Required

The equation

First, calculate the equation from the zeros

$y =k(x - x_1)(x - x_2)$

Substitute $x_1 = -2$ and $x_2 = 3$

$y =k(x - -2)(x - 3)$

$y =k(x +2)(x - 3)$

To solve for k, we substitute $(x,y) = (-1,2)$

$2 = k(-1+2)(-1-3)$

$2 = k(1)(-4)$

$2 = -4k$

Divide by -4

$k=\frac{2}{-4}$

$k=-\frac{1}{2}$

So, the equation is:

$y =k(x +2)(x - 3)$

$y =-\frac{1}{2}(x +2)(x - 3)$

8 0

3 years ago

Exposure to microbial products, especially endotoxin, may have an impact on vulnerability to allergic diseases. The following ar

Softa [21]

Answer:

A. E ( U ) = 21.5454 , E ( F ) = 8.39333

B. M ( U ) = 17.0 , M ( F ) = 18.0

C. E ( U' ) = 17.0 , E ( F' ) = 7.95384

D. T ( U ) = 9.091% , T ( F ) = 6.667%

Step-by-step explanation:

Solution:-

- Two sample sets ( U ) and ( F ) that define the concentration ( EU/mg ) of endotoxin found in urban and farm homes as follows:

U: 6.0 5.0 11.0 33.0 4.0 5.0 80.0 18.0 35.0 17.0 23.0

F: 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 22.0 9.6 2.0 2.0 0.5

- To determine the mean of a sample E ( U ) or E ( F ) the following formula from descriptive statistics is used:

$E ( X ) = Sum ( X_i ) / n$

Where,

Xi : Data iteration

n: Sample size

Therefore,

$E ( U ) = \frac{Sum (U_i )}{n_u} \\\\E ( U ) = \frac{6.0 + 5.0 + 11.0 + 33.0 + 4.0+ 5.0 +80.0+ 18.0+ 35.0+ 17.0+ 23.0 }{11} \\\\E ( U ) = 21.54545\\\\E ( F ) = \frac{Sum (F_i )}{n_f} \\\\E ( F ) = \frac{2.0 + 15.0 + 12.0 + 8.0 + 8.0 + 7.0 + 6.0 + 19.0+ 3.0+ 9.8+ 22.0+ 9.6+ 2.0+ 2.0+ 0.5 }{15} \\\\E ( F ) = 8.39333$

- To determine the sample median we need to arrange the data for both samples ( U ) and ( F ) in ascending order as follows:

U: 4.0 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0 80.0

F: 0.5 2.0 2.0 2.0 3.0 6.0 7.0 8.0 8.0 9.6 9.8 12.0 15.0 19.0 22.0

- Now find the mid value for both sets:

Median term ( U ) = ( n + 1 ) / 2

= ( 11 + 1 ) / 2 = 12/2 = 6th term

Median ( U ), 6th term = 17.0

Median term ( F ) = ( n + 1 ) / 2

= ( 15 + 1 ) / 2 = 16/2 = 8th term

Median ( F ), 8th term = 8.0

- We will now trim the smallest and largest observation from each set.

- In set ( U ) we see that smallest data corresponds to ( 4.0 ) while the largest data corresponds to ( 80.0 ). We will exclude these two terms and the trimmed set is defined as:

U': 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0

- In set ( F ) we see that the smallest data corresponds to ( 0.5 ) while the largest data corresponds to ( 22.0 ). We will exclude these two terms and the trimmed set is defined as:

F': 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 9.6 2.0 2.0

- We will again use the previous formula to calculate means of trimmed samples ( U' ) and ( F' ) as follows:

$E ( U' ) = \frac{5.0+ 5.0+ 6.0+ 11.0+ 17.0+ 18.0+ 23.0+ 33.0+ 35.0}{9} \\\\E ( U' ) = 17$

$E ( F' ) = \frac{2.0 +2.0+ 2.0 +3.0+ 6.0+ 7.0+ 8.0+ 8.0+ 9.6+ 9.8+ 12.0+ 15.0+ 19.0}{13} \\\\E ( F' ) = 7.95384$

- The trimming percentage is known as the amount of data removed from the original sample from top and bottom of sample size of 11 and 15, respectively.

- We removed the smallest and largest value from each set. Hence, a single value was removed from both top and bottom of each data set. We can express the trimming percentage for each set as follows:

$T ( U ) = \frac{1}{11} * 100 = 9.091\\\\T ( F ) = \frac{1}{15} * 100 = 6.667$ %

- The trimming pecentages for each data set are 9.091% and 6.667% respectively.

7 0

4 years ago

In 1924, the temperature in Fairfield, Montana, dropped from 63 degrees to -21 degrees in 12 hours. What was the change in tempe

lapo4ka [179]

The answer would be -42.

7 0

3 years ago