One more question, Will pick brainliest + extra points!! Find x!!

Mathematics

2 answers:

kvv77 [185]2 years ago

7 0

Since the triangle ADC is an enlargement of triangle AEB, 48 divided by the enlargement factor will give you 3x.
The enlargement factor is:
= 60/30
= 2

Therefore:

3x = 48/2

3x = 24

3x/3 = 24/3

x = 8

Cerrena [4.2K]2 years ago

5 0

Here, as the sides are equal, middle line would be exact half then the longer (bottom) side of the triangle.
48 = 2(3x)
6x = 48
x = 48/6
x = 8

In short, Your Answer would be Option D

Hope this helps!

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S KM ∥ JN? Why or why not?

bixtya [17]

Given: We have the given figure through which we can see

LK=16,

KJ=10,

LM=24,

MN=15

To Find: Whether KM || JN and the reasoning behind it.

Solution: Yes, KM || JN because $\frac{16}{10}= \frac{24}{15}$

Explanation:

For this solution, we use the concept of Similar Triangles.

Now, KM || JN if ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).

Now, ∠MLK=∠NLJ

To prove similarity of the two triangles, we have to show that the sides are proportional. In other words, LK:KJ = LM:LN

$LK:KJ=LM:LN\\\\ \frac{LK}{KJ} =\frac{LM}{LN}\\\\\frac{16}{26}= \frac{24}{39}\\\\$

which is true as both sides simplify to $\frac{8}{13}$

Thus, we see that ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).

Therefore, KM || JN.

To come to the reasoning, notice that

$\frac{LK}{LJ} =\frac{LM}{LN}\\\\\frac{LK}{LK+KJ} =\frac{LM}{LM+MN}\\\\\frac{LK+KJ}{LK} =\frac{LM+MN}{LM}\\\\1+\frac{KJ}{LK}=1+ \frac{MN}{LM}\\\\\frac{LK}{KJ} =\frac{LM}{MN}$