4. A plane was flying at an altitude of 55,000 feet when it began the descent toward the airport. The airplan
2 answers:
You might be interested in
Step-by-step explanation:
1) the required equation in common form is:
(x-x₀)²+(y-y₀)²=r², where (x₀;y₀) - coordinates, where Michael is standing; r - the social distance;
According to the common form and given coordinates (x₀=-5; y₀=2; r=6) it is possible to make up the required equation:
<u>(x+5)²+(y-2)²=6².</u>
2) if the distance between two friends is:
this distance is longer than social (6 ft). For more info see the attachment.
