To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
Answer:
2
Step-by-step explanation:
I dont know for sure though...
Answer:
(A) No solution
(B) One solution
(C) One solution
(D) One solution
(E) No solution
Please tell me if this is incorrect. I hope this helps!
Answer:
y=1/2x+1
Step-by-step explanation:
First use slope formula.

Plug in the information needed.

The slope is
.
Now, use point-slope formula.
y-y1=m(x-x1)
Plug in the information needed.
y-3=1/2(x-4)
y-3=1/2x-2
y=1/2x+1
The equation of the line in slope-intercept form is y=1/2x+1.
Hope this helps!
If not, I am sorry.
Answer:
Direct Variation Use y=kx. Means “y varies directly with x.” k is called the constant of variation. “y varies inversely with x.” k is the constant of variation.
Step-by-step explanation: