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Nookie1986 [14]
3 years ago
6

Find the interval(s) on which the function is increasing.

Mathematics
2 answers:
Tatiana [17]3 years ago
4 0

Answer:

II (THE Second one )

Step-by-step explanation:

Because when you substitute X by (-2)

you will get :

y=(-2)^2 - 6(-2) - 16 = Zero

So, -2 is not including in the interval .

jarptica [38.1K]3 years ago
4 0
The second one.......
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SoIve the system of equations by elimination. (Addition)<br> 1)-2x + 4y = -22<br> 2x + 8y = –26
Rufina [12.5K]

Answee:

We have these two equations:

-2x +4y =-22

2x + 8y -26

We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:

2x + 8y =-26  ---- -2x - 8y =26

Now we have this:

-2x +4y = -22

-2x -8y = 26

Now e substract both equations:

-2x - (-2x) +4y -(-8y) = -22-26

12y = -48

Y = -48/12 = -4

And we replace to get x

-2x + 4y = -22

-2x +4*(-4)=-22

-2x - 16 = -22

x= -6/-2 =3

6 0
3 years ago
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Use the Adding Integers manipulative to create a tile model for this situation: What is the sum of (-5) + (+3)?
Karo-lina-s [1.5K]

Answer:

-2

Step-by-step explanation:

(-5) + (+3)

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2 years ago
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A birthday candle costs $0.84. How much do 6 birthday candles cost?
spin [16.1K]

Answer:

$5.04

Step-by-step explanation:

Take the cost of one candle and multiply the number of candles desired

6 *.84 =5.04

4 0
3 years ago
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What the algebraic expression for the difference of 8 and a number?
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8-n
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3 years ago
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Circle the correct words in each of the following statements.Given that x(t) is a real function with the Fourier transform X(f):
Kryger [21]

Answer:

(a) even function

(b) odd function

Step-by-step explanation:

From the given information;

Any function x(t) can be said to be the sum of even and odd functions.

i.e.

x(t) = x_e(t) + x_o(t)

where;

x(t) is a real function.

For a  real and even function, the Fourier transform is also real and even.

x_e(t)  \iff x_e(f) \\ \\

Also, the Fourier Transform of a real and odd function is imaginary and odd.

x_o(t) \iff x_o(f)

The behavior of X(f) largely depends on the behavior of x(t).

If x(t) is real and even, then x(f) is real and even valued function

Thus, the real part of X(f) is an even function.

If x(t) is real and odd, then x(f) is imaginary and odd valued function

Thus, the imaginary part of X(f) is an odd function.

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