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goldfiish [28.3K]
3 years ago
15

V = 1/3 bh for b the base of the cone

Mathematics
1 answer:
ch4aika [34]3 years ago
6 0

Answer:

\huge\boxed{b=\dfrac{3V}{h}}

Step-by-step explanation:

V=\dfrac{1}{3}bh\qquad\text{multiply both sides by 3}\\\\3V=3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}bh\\\\3V=bh\qquad\text{divide both sides by}\ h\neq0\\\\\dfrac{3V}{h}=\dfrac{bh}{h}\\\\\dfrac{3V}{h}=b\to \boxed{b=\dfrac{3V}{h}}

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In this fulcrum, for the weights to be balance, what do the distances d1 and d2 have to be if the overall length is 12 feet?
mel-nik [20]
For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.

Let d1= x. since total distance is 12, we can write d2 = 12 - x

for the fulcrum to balance:

60x = 50(12 - x)

60x = 600 - 50x

110x = 600

x = 5.45

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5 0
3 years ago
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tia_tia [17]

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Step-by-step explanation:

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Step-by-step explanation:

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