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hjlf
3 years ago
8

Solve the inequality 2x - 3 < x + 2 ≤ 3x + 5. Show your work.?

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
Add like terms and put x in the middle.
-3 < -2x + x - 3x ≤ 5 - 2
-3 < - 4x ≤ 3
Sign changed when divide by negative numbers
(3/4) > x ≥ (-3/4)
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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
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(a) 120 choices

(b) 110 choices

Step-by-step explanation:

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nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

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Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

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3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

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