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3 years ago

Is 11p-7q polynomial

2 answers:

7 0

Answer: Yes; this is polynomial.

Specifically, it is a "polynomial EXPRESSION" ; but not a "polynomial equation" ; because it is not an "equation.

There are more than one variables/variable expressions, so it is a polynomial.

Veseljchak [2.6K]3 years ago

3 0

Answer: The answer is Yes :)

Step-by-step explanation: I don't know why but I just took the test and the answer was yes. I hope this helps :)

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Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro

lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that $\mu = 0, \sigma = 1$

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{-1.69 - 0}{1}$

$Z = -1.69$

$Z = -1.69$ has a p-value of 0.0455

X = -2.23

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{-2.23 - 0}{1}$

$Z = -2.23$

$Z = -2.23$ has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0

3 years ago

The perimeter of a particular square and the circumference of a particular circle are equal. What is the ratio of the area of th

oksano4ka [1.4K]

<h2>Ratio of area of the square to the area of the circle = π/4</h2>

Step-by-step explanation:

Let the side of square be a and radius of circle be r.

The perimeter of a particular square and the circumference of a particular circle are equal.

Perimeter of square = 4 x a = 4a

Circumference of circle = 2πr

Given that

4a = 2πr

$a=\frac{\pi r}{2}$

We need to find the ratio of the area of the square to the area of the circle.

Area of the square = a²

Area of the circle = πr²

$\texttt{Ratio of area of the square to the area of the circle =}\frac{a^2}{\pi r^2}\\\\\texttt{Ratio of area of the square to the area of the circle =}\frac{\left ( \frac{\pi r}{2}\right )^2}{\pi r^2}\\\\\texttt{Ratio of area of the square to the area of the circle = }\frac{\pi}{4}$

Ratio of area of the square to the area of the circle = π/4

6 0

3 years ago

Find the equation of a plane that is perpendicular to the vector −4i⃗ −4j⃗ −k⃗ and passing through the point (−2,−5,5)

vredina [299]

hello ....

the equation of a plane that is ; ax+by+cz +d =0

the vector perpendicular to this plane is : V(a,b,c)

in this exercice ; a = -4 b= -4 c = -1

then: the equation of a plane that is ; -4x-4y-z +d =0

but the plane passing through the point (−2,−5,5) :

-4(-2)-4(-5)-(5) +d =0

23+d =0

d =-23

the equation of a plane is : -4x-4y-z-23 =0

5 0

4 years ago

What is the equation in point-slope form of a line that passes through the points (3, −5) and (−8, 4) ?

maxonik [38]

ANSWER

$y + 5= - \frac{9}{11} (x-3)$

or

$y - 4= - \frac{9}{11} (x + 8)$

EXPLANATION

We want to find the equation in point-slope form of a line that passes through the points (3, −5) and (−8, 4).

The point-slope form is given by;

$y-y_1=m(x-x_1)$

where

$m = \frac{4 - - 5}{ - 8 - 3} = \frac{4 + 5}{ - 11} = - \frac{9}{11}$

is the slope of the line.

If

$(x_1,y_1)=(3,-5)$

The point-slope form is

$y + 5= - \frac{9}{11} (x-3)$

On the other hand, if
$(x_1,y_1)=( - 8,4)$

Then the point-slope form is,

$y - 4= - \frac{9}{11} (x + 8)$

These two equations are the same when simplified.

4 0

3 years ago

Select 3 !! Please help!! Precal A in connexus

barxatty [35]

Answer:

I believe its A C and E

hope this helps also may i have Brainleast?

Step-by-step explanation:

3 0

3 years ago