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3 years ago

ALGEBRA 1, SEM. 2; PLEASE SHOW WORK f(x)=x2+4x+7 in vertex form

Mathematics

2 answers:

Elina [12.6K]3 years ago

5 0

f(x) = x^2 + 4x + 7

f(x) = x^2 + 4x + 4 + 3

f(x) = (x + 2)^2 + 3

Vertex (h, k) where h = - 2 and k = 3

So vertex (-2 , 3)

emmasim [6.3K]3 years ago

4 0

$f(x)=x^2+4x+7 \\ f(x)=x^2+4x+4+3\\ f(x)=(x+2)^2+3$

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