Question

ALGEBRA 1, SEM. 2; PLEASE SHOW WORK f(x)=x2+4x+7 in vertex form

Answer 1

f(x) = x^2 + 4x + 7

f(x) = x^2 + 4x + 4 + 3

f(x) = (x + 2)^2 + 3

Vertex (h, k) where h = - 2 and k = 3

So vertex (-2 , 3)

Answer 2

$f(x)=x^2+4x+7 \\ f(x)=x^2+4x+4+3\\ f(x)=(x+2)^2+3$