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solniwko [45]
2 years ago
15

F(x)=1/3x+7 find inverse

Mathematics
1 answer:
jeka942 years ago
8 0

Answer:

Step-by-step explanation:

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From the parent function LaTeX: f\left(x\right)=\frac{5}{x}f ( x ) = 5 x, write the equation of the function g(x) if f(x) is tra
madreJ [45]

Answer:

idk

Step-by-step explanation:

5 0
3 years ago
Please help I will mark brainliest!!!!!!
balu736 [363]
Fifucfucufcifcir ruvif if rictvifcfict
7 0
3 years ago
Lara is a 50% partner. She is guaranteed payment of no less than 20,000. The partnership's income before deducting guaranteed pa
enyata [817]

Answer:

Lara's share = 25000

Step-by-step explanation:

Partnership's income = 50,000

Lara's guaranteed payment = 20,000

As the Income 50,000 is larger than Lara's guaranteed payment i.e 20,000. Since Lara is 50% partner so she will receive half the amount of the partnership's income.

Partnership's Income = 50,000  

Half of Partnership's income = 50,000/2

                                                = 25,000

Therefore, Lara's distributive share is 25,000.

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8 0
3 years ago
CALC- limits<br> please show your method
gladu [14]
A. Factor the numerator as a difference of squares:

\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6

c. As x\to\infty, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4

e. Let's first rewrite the root terms with rational exponents:

\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}

Next we rationalize the numerator and denominator. We do so by recalling

(a-b)(a+b)=a^2-b^2
(a-b)(a^2+ab+b^2)=a^3-b^3

In particular,

(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3
(x^{1/2}-x)(x^{1/2}+x)=x-x^2

so we have

\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}

For x\neq0 and x\neq1, we can simplify the first term:

\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x

So our limit becomes

\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43
3 0
3 years ago
The cruising speed of the bullet train will be at least 170 miles per hour. Use s to represent the train's cruising speed (in mi
salantis [7]

Answer:

s ≥ 170

Step-by-step explanation:

The problem raises the following statement: "The cruising speed of the bullet train will be at least 170 miles per hour"

Which means that the train has a speed of 170 miles for now or higher, knowing this we can pose the inequality.

Knowing that "s" is the train's cruising speed (in miles per hour), we have to:

s ≥ 170

This would be the inequality that the statement represents.

6 0
3 years ago
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