Answer:
5 minutes
Step-by-step explanation:
We know that 1760 yards are in a mile. We can convert the given info into a proportion. 440/75 = 1760/x, where x is the number of seconds it takes to run a mile. Cross-multiply to get 440x = 75*1760. Divide both sides by 440 to get x = 75*4 = 300 seconds. The problem asks for how many minutes so you have to convert 300 seconds to minutes. To do this, we have to divide 300 by 60 to get 5 minutes.
Answer:
The answer is $1.70
Step-by-step explanation:
If 6 plums are $1.50 you would divide $1.50 by 6 to get the unit cost, $.25. Then you do the same thing for the apples. $3.00 divided by the 5 apples is $.60. Now you need to multiply both unit costs by 2 then add them together to get $1.70
(plums) $1.50 / 6 = .25
(apples) $3.00 / 5 = .60
(plums) .25 x 2 = .50
(apples) .60 x 2 = $1.20
$1.20 + .50 = $1.70
Hopefully I could help!!
Reason:
2. SD ⊥ HT. ∴ ∠SDH = ∠SDT =90°
3. Given (It is given in the question)
5. RHS congruence
(Here, the right angle, hypotenuse and one side of ΔSHD is congruent to that of ΔSTD).
Statement:
4. Line segment SD = SD
(Reflexive property is used to prove congruence of triangles. This property is used when an angle or line segment is congruent to itself.)
Certin, because they can be any two cards.
Answer:
P = 0.006
Step-by-step explanation:
Given
n = 25 Lamps
each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours
Find probability that the lamp will be burning at end of 1300 hours period.
As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have
Suppose i represents lamps
P (∑i from 1 to 25 (
> 1300)) = 1300
= P(
> 
) where represents mean time of a single lamp
= P (Z> 
) Z is the standard normal distribution which can be found by using the formula
Z = Mean Time () - Life time of each Lamp (50 hours)/ (SD/
)
Z = (52-50)/(4/
) = 2.5
Now, P(Z>2.5) = 0.006 using the standard normal distribution table
Probability that a lamp will be burning at the end of 1300 hours period is 0.006
