Answer:
51.96 mm² approximately
Step-by-step explanation:
the first thing you should know is that the area of a rectangle is base*height sin of (
the included angle i.e
Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°
<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>
Aparallelogram= bh sin of sin of the included angle
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately
angles EFH and GFH are congruents
for the second equivalence criterion two triangles are equivalents if they have respectively 2 angles and 1 side congruents
the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.
so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:
EH=HG
s+36=7s
s+36-7s=0
s-7s=-36
-6s=-36
6s=36
s=6
<em>sorry for my english</em>
Answer:
I cant see it....
Step-by-step explanation:
I cant see it....
Answer: I believe your answer is C.
÷
. . .
÷
=11.5