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tatyana61 [14]
3 years ago
11

Write an absolute value equation with-1 and 5 as the solution.

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

it is detailed solution. please mark brainlest.

Thank you have a nice day

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If 17y-24y+13y=210+y, what is the value of y?
Debora [2.8K]
17y - 24y + 13y = 6y
6y - y = 5y
5y = 210
\frac{210}{5}

210/5 =42
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What is the value of X? Enter your answer as a decimal in the box. Round only your final answer to the nearest 10th.
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14 less than the quotient of 63 and a number H
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3 years ago
You are dealt one card from a standard​ 52-card deck. Find the probability of being dealt a card greater than 2 and less than 5.
sladkih [1.3K]

Answer:

p =\frac{Possible cases}{Total cases}

And replacing 8 for the possible cases and 52 for the total number of cards for a single selection we got:

p =\frac{8}{52}= 0.154

Step-by-step explanation:

For a standard deck we need to remember that we have 4 types suits of Spades, Hearts, Diamonds, and Clubs. And in total 13 possible options A,2,3,4,5,6,7,8,9,10,J,Q,K.

If we want the probability that a card selected would be greater than 2 and less than 5 means that we are interested in the cards with denomination 3's and 4's because the card can't be 2 or 5.

And from the previous info we know that we have four cards for the 4's and four for the 3's so then we have a total of 8 possible cards in the standard deck of 52 who satisfy the conditions required.

And then we can find the probability desired with this formula:

p =\frac{Possible cases}{Total cases}

And replacing 8 for the possible cases and 52 for the total number of cards for a single selection we got:

p =\frac{8}{52}= 0.154

3 0
3 years ago
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