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ElenaW [278]
3 years ago
6

Add 34 and 6 and then multiply by 3

Mathematics
2 answers:
Sophie [7]3 years ago
5 0

3(34+6)=90

add 34 and 6 together in the parenthesis and then multiply the sum by 3.

Juli2301 [7.4K]3 years ago
5 0
The answer that ur looking for is 52 and ur welcome
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Please help ! I don’t get it!
Amiraneli [1.4K]

Answer:

PR = 16

SR = 12

Step-by-step explanation:

6/8 = (x-3)/(x+1)

8x-24 = 6x+6

simplify

2x = 30

x = 15

PR = 15 + 1 = 16

SR = 15 - 3 = 12

8 0
2 years ago
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!<br><br><br> Please explain this!!!
finlep [7]

First, multiply the first equation by 3 to get:

3x+3y=-6

Then, add the two equations together to get

8x=16

We can follow that x=2. Plugging in x=2, we get that y=-4.

Therefore, the solution of (2,-4)

7 0
3 years ago
Read 2 more answers
Need the answer quick!
nika2105 [10]
Hey! Try plugging in the given coordinates and equations into a scientific calculator
6 0
3 years ago
Do question a,b,c,d plz
julsineya [31]
A) 13.25
B) 164.64
C) 57.1
D) 145173.954289 or <span>381.017</span><span>​<span>2

A good calculator website is </span></span>https://www.cymath.com/
4 0
3 years ago
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