Answer:
it is equals to 3 okay ^^
<span><span><span>s+12</span>+<span>3s</span></span>−8</span><span>=
<span><span><span><span>s+12</span>+<span>3s</span></span>+</span>−8
</span></span>Combine Like Terms<span>
<span><span><span>s+12</span>+<span>3s</span></span>+<span>−8</span></span></span><span>=
<span><span>(<span>s+<span>3s</span></span>)</span>+<span>(<span>12+<span>−8</span></span>)</span></span></span><span>=
<span><span>4s</span>+<span>4</span></span></span>
Answer: -7
Step-by-step explanation:
-30 = 5(x + 1)
-30 = 5x + 5. ( After distrbuting the 5)
-5. -5
-30 - 5. = 5x
-35 = 5x
x = -7
Answer:
d = kr
Explanation:
We know that the depth (d) varies directly with the amount of rain (r).
This means that as the amount of rain increases, the depth increases and vice-versa.
The depth would depend on r multiplied by a constant of variation (k)
Translating this into equation, we would get the following:
d = kr
Hope this helps :)
Answer:
t ∈ {1, 3}
Step-by-step explanation:
You want to find t such that ...
h = 27
27 = -8t^2 +32t +3 . . . . . . substitute the expression for h
24 = -8t^2 +32t . . . . . . . . . subtract 3
-3 = t^2 -4t . . . . . . . . . . . . . divide by -8
1 = t^2 -4t +4 = (t -2)^2 . . . . add 4 to complete the square
±√1 = t -2 . . . . . . . . . . . . . . take the square root
t = 2 ± 1 . . . . . . . . . . . . . . . . add 2
t = 1 or 3
The object is 27 ft off the ground at t = 1 and again at t = 3.
