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3 years ago

Simplify (-63) ÷ (-9)

Mathematics

2 answers:

Julli [10]3 years ago

6 0

Dividing two negatives equals a positive:
(-63) / (-9) = 7

sasho [114]3 years ago

3 0

Answer:

Find the GCD (or HCF) of numerator and denominator

GCD of 63 and 9 is 9

Divide both the numerator and denominator by the GCD

63 ÷ 9

9 ÷ 9

Reduced fraction:

7/1

Therefore, 63/9 simplified to lowest terms is 7/1.

Step-by-step explanation:

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Area ÷ Width = length

Area Width
20.5 ÷ 2.5 = 8.2

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3 years ago

Write a percent between 25% and 50%.then write it as a decimal and as a fraction in simplest form

JulsSmile [24]

One possiablilty is 33%, .33, 1/3.

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3 years ago

A farmer is going to divide her 30 acre farm between two crops. Seed for crop A costs $5 per acre. Seed for crop B costs $10 per

jenyasd209 [6]

Answer:

30 acres of A

0 acres of B

Step-by-step explanation:

On forming the equations we get

Acres = A+B $\leq$ 30 .............(1)

Seed = 5A + 10B $\leq$ 200 ...........(2)

Profit = 160A+50B

Upon rearranging this we get

A= 30-B sing equation (1)

A=40-2B using equation (2)

On plotting these inequalities on the cartesian planes we will get the following points of intersection (0,20) (20,30) (30,0)

Now using these coordinates (A,B) to get Maximum profit

P= $1000 for (0,20)

P=$4700 for (20,30)

P= $4800 for (30,0)

clearly for (30,0) we will get the maximum profit on the crops

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3 years ago

8 = 3a – 4 what is value of a ?

expeople1 [14]

Answer:

a=4

Step-by-step explanation:

8=3a-4

12=3a

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7 0

3 years ago

Suppose that the distance, in miles, that people are willing to commute to work is an exponential random variable with a decay p

garik1379 [7]

Answer:

m = $\frac{1}{20}$
μ = 20
σ = 20

The probability that a person is willing to commute more than 25 miles is 0.2865.

Step-by-step explanation:

Exponential probability distribution is used to define the probability distribution of the amount of time until some specific event takes place.

A random variable X follows an exponential distribution with parameter m.

The decay parameter is, m.

The probability distribution function of an Exponential distribution is:

$f(x)=me^{-mx}\ ;\ m>0, x>0$

Given: The decay parameter is, $\frac{1}{20}$

X is defined as the distance people are willing to commute in miles.

The decay parameter is m = $\frac{1}{20}$ .
The mean of the distribution is: $\mu=\frac{1}{m}=\frac{1}{\frac{1}{20}}=20$ .
The standard deviation is: $\sigma=\sqrt{variance}= \sqrt{\frac{1}{(m)^{2}} } =\frac{1}{m} =\frac{1}{\frac{1}{20}} =20$

Compute the probability that a person is willing to commute more than 25 miles as follows:

$P(X>25)=\int\limits^{\infty}_{25} {\frac{1}{20} e^{-\frac{1}{20}x}} \, dx \\=\frac{1}{20}|20e^{-\frac{1}{20}x}|^{\infty}_{25}\\=|e^{-\frac{1}{20}x}|^{\infty}_{25}\\=e^{-\frac{1}{20}\times25}\\=0.2865$

Thus, the probability that a person is willing to commute more than 25 miles is 0.2865.

7 0

4 years ago