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2 years ago

Apply the distributive property to create an equivalent expression. 9(a + 4b + 3c)

Mathematics

1 answer:

MrMuchimi2 years ago

3 0

$\rm9(a + 4b + 3c) \\ 9(a) + 9(4b) \rm+ 9(3c) \\ \rm 9a + 36b + 27c \\ \therefore \tt9(a + 4b + 3c) = 9a + 36b + 27c$

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An education firm measures the high school dropout rate as the percentage of 16 to 24 year olds who are not enrolled in school a

posledela

Answer:

The value of the test statistic $z = -0.6606$

Step-by-step explanation:

From the question we are told that

The high dropout rate is $\mu = 6.1$ % $= 0.061$

The sample size is $n = 1000$

The number of dropouts $x = 56$

The probability of having a dropout in 1000 people $\= x = \frac{56}{1000} = 0.056$

Now setting up Test Hypothesis

Null $H_o : p = 0.061$

Alternative $H_a : p < 0.061$

The Test statistics is mathematically represented as

$z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }$

substituting values

$z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }$

$z = -0.6606$

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3 years ago

Choose the value for x that solves this equation. 0 = -2x + 6

lana66690 [7]

Answer:

x = 3

Step-by-step explanation:

Hi there !

0 = - 2x + 6

2x = 6

x = 6 : 2

x = 3

Good luck !

7 0

3 years ago

Write an equation for the line that has a slope of 6 and passes through the point 4, 4

Rudik [331]

Answer:

y = 6x - 20

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 6, thus

y = 6x + c ← is the partial equation

To find c substitute (4, 4) into the partial equation

4 = 24 + c ⇒ c = 4 - 24 = - 20

y = 6x - 20 ← equation of line

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3 years ago

Angle CMW and angle WML together form angle CML. Angle CMW is a right angle. What must be true about angle CML?

ANTONII [103]

CML must be an obtuse angle.

Since CMW and WML together form CML, and CMW is a right angle, then CML must be larger than a right angle, which makes it obtuse.

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3 years ago

LITERAL EQUATIONS K= AP/2 SOLVE FOR A

kvv77 [185]

$K=\frac{AP}{2}\ \ \ \ |Multiply\ by\ 2\\\\
2K=AP \ \ \ \ \ |Divide\ by\ P\\\\
\frac{2K}{P}=A\\\\Solution\ is\ A=\frac{2K}{P}.$

4 0

3 years ago

Apply the distributive property to create an equivalent expression. 9(a + 4b + 3c)​

Apply the distributive property to create an equivalent expression. 9(a + 4b + 3c)