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Aneli [31]
3 years ago
14

Which of the following equations have no solutions?

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
6 0

Answer:it’s actually -60x + 32 = -60x + 60

And

-60x +32 = -60x-32

Step-by-step explanation:

krok68 [10]3 years ago
4 0

Answer:

-60.X + 32 = 32.r – 60

Because we only have one equation for 2 unknowns.

Step-by-step explanation:

All the equations have solution for r but the one that has 2 unknowns (r and X).

That is because we only have one equation and 2 unknowns.

Then, we only can express one unknown in function of the other and have an indeterminate solution.

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Lunna [17]

Answer:

b=66

Step-by-step explanation:

80-14 is 66, therefore b=66

5 0
3 years ago
How do i solve this |6x-3|=7
Y_Kistochka [10]

Answer:

x=5\3,-2\3

Step-by-step explanation:

7 0
3 years ago
Some people took part in a game. The frequency shows information about their scores.
Marizza181 [45]

Answer:

The mean = 17.54

Step-by-step explanation:

Form a table as below;

<u>Interval         Frequency{f}      Midpoint of frequency{x}          fx    </u>

1-7                    19                         4                                            76

8-10                  14                         9                                            126

11-15                  15                         13                                           195

16-20                20                        18                                           360

21-35                 10                        28                                          280

36-50                13                         43                                          559

Sum                   91                                                                        1596

The mean  of grouped data = Sum of { Interval Midpoint * Frequency } /Sum of frequency

The mean= 1596 / 91

The mean = 17.54

5 0
3 years ago
All rectangles are paralloelograms
Anni [7]

Answer:

not all rectangles are paralloelograms.

Step-by-step explanation:

8 0
3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
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