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Lera25 [3.4K]
3 years ago
6

so I have these questions for homework where you have to come up with the probabilities for each outcome based on a tree diagram

, ill be able to send you the problem, can you help me solve it?​
Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

Sure

Can you please mark me brainliest :)

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PLease help me on this I have ten minutes left
Harlamova29_29 [7]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
7) Original price: ?<br> Discount: 25%<br> Sale price:<br> $28
Studentka2010 [4]

Answer:

Step-by-step explanation:

let be x the price before the discount

original price= 28/(1-0.25)=28/0.75=37.33

original price=37.33

3 0
3 years ago
Read 2 more answers
An article in USA Today stated that Internal surveys paid for by directory assistance providers show that even the most accurate
MariettaO [177]

Answer:

a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %

Step-by-step explanation:

a. This is a binomial probability.

Let q = probability of giving out wrong number = 15 % = 0.15

p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75

For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹

= 10(0.15)(0.75)⁹

= 1.5(0.0751)

= 0.1126

= 11.26 %

b. At most one wrong is P(x ≤ 1) = P(0) + P(1)

= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹

= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹

= 0.0563 + 0.01126

= 0.06756

= 6.756 %

≅ 6.76 %

Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.

3 0
3 years ago
Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ
liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

  • Mx(x,y) = d/dx 8x²y = 16xy
  • Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2

We conclude that the line integral is 1/2

4 0
3 years ago
6x^2 + 23x + 7 NEED HELP SOLVING QUADRATIC EQUATION
luda_lava [24]

Answer:

6x2 + 23x + 7 = 0

Factorization:

(2x + 7)(3x + 1) = 0

Solutions based on factorization:

2x + 7 = 0   ⇒   x1 = −7

2

= −3.5

3x + 1 = 0   ⇒   x2 = −1

3

≈ −0.333333

Extrema:

Min = (−1.916667, −15.041667)

Step-by-step explanation: hope this helps

6 0
4 years ago
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