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Valentin [98]
3 years ago
11

Given: 3j+k/2=15-4k; Prove j=10-3k And Given 5x-2y=x+14; Prove y=2x-7

Mathematics
1 answer:
baherus [9]3 years ago
4 0

Answer:

I LIKE TRAINS

Step-by-step explanation:

TRAINS 34

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Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
ankoles [38]

Option C:

2 g^{3}-5 g^{2}+6

Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

8 0
3 years ago
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Step-by-step explanation:

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levacccp [35]

Answer:

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Step-by-step explanation:

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8 0
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Hi can someone please answet this question for me im a bit confused
Jobisdone [24]

Answer:

a)

Step-by-step explanation:

for each point (A, B, C) reduce the 'x-value' by two and reduce the 'y-value' by 7

for example, for point A:

to find A':  (-6, -7) would be (-6-2, -7-7)  which is (-8, -14)

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