The percentage of sugar in the solution is 1%
To solve this question, we need to find the percentage of 6 out of 600.
Data given;
- mass of sugar = 6g
- mass of solution = 600g
<h3 /><h3>What is Percentage</h3>
This is the rate or proportion of a substance in the total value and multiplied by 100.
The percentage of sugar in the solution is calculated by
The percentage of sugar in the solution is 1%
Learn more about percentage here;
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Answer:
Explanation:
Use the trigonometric ratio definition of the tangent function and the quotient rule.
Quotient rule: the derivative of a quotient is:
- [the denominator × the derivative of the numerator less the numerator × the derivative of the denominator] / [denominator]²
- (f/g)' = [ g×f' - f×g'] / g²
So,
- tan(x)' = [ sin(x) / cos(x)]'
- [ sin(x) / cos(x)]' = [ cos(x) sin(x)' - sin(x) cos(x)' ] / [cos(x)]²
= [ cos(x)cos(x) + sin(x) sin(x) ] / [ cos(x)]²
= [ cos²(x) + sin²(x) ] / cos²(x)
= 1 / cos² (x)
= sec² (x)
The result is that the derivative of tan(x) is sec² (x)
To calculate the amount of heat entering or leaving a system, the equation <span>Q=mcΔT</span> is used.
Explanation:
m = mass (in grams)
c = specific heat capacity (J/g°C)
ΔT = change in temperature (°C)
Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.
The mass given is 25.0 grams.
As for the change in temperature, I will assume that it start off at room temperature, 25°C.
<span>25°C−0°C=25°C</span>
<span>Q=mcΔT</span>
<span>Q=25grams⋅4.19<span>J<span>g°C</span></span>⋅25°C</span>
<span>Q=2618.75J</span>
Take into account significant figures and the answer should be
<span>2.6⋅<span>103</span><span>J</span></span>
Answer:
Cuando un átomo neutro gana uno o más electrones, el número de electrones aumenta mientras que el número de protones en el núcleo permanece igual. El resultado es que el átomo se convierte en un anión, un ion con una carga neta negativa.
Explanation:
Because Mitosis is used for growth and repair